Question

The divisor and quotient of the number 6123 are same and the remainder is half the divisor. Find the diviso

Answer 1

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Answer 2

Answer:

$78 or \frac{-157}{2}$

Step-by-step explanation:

Let the divisor be x

Since The divisor and quotient of the number 6123 are same

So, quotient = x

Dividend = 6123

The remainder is half the divisor.

So, Remainder = $\frac{x}{2}$

Since we know that

$Dividend = (Divisor \times Quotient)+Remainder$

$6123 = (x \times x)+\frac{x}{2}$

$6123 = x^2+\frac{x}{2}$

$6123 \times 2= 2x^2+x$

$12246= 2x^2+x$

$2x^2+x-12246=0$

$(x-78)(2x+157)=0$

$x=78,\frac{-157}{2}$

Hence the divisor can be $78 or \frac{-157}{2}$