the domain function of fx=√x-4 + √x-5 + |x| + x2
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as we can substitute an real values of x in |x| and (x^2) so the problem arises in √(x-4) and √(x-5) as we cannot put any negative values in √( )
so
x - 4 > 0 ......and...... x - 5 > 0
so
x > 4....and......x > 5
so x should be greater than 5
so domain of f(x) is
[5,∞)
so
x - 4 > 0 ......and...... x - 5 > 0
so
x > 4....and......x > 5
so x should be greater than 5
so domain of f(x) is
[5,∞)
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