Math, asked by poshanshankar, 19 days ago

.The domain of the function f(x) = x^2/1+x^2 is (a) R                                   (b) R-{-1,1}                    (c)  [0,1)              d) R –{0}​

Answers

Answered by Kaidou
2

Answer:

B

Step-by-step explanation:

Domain:

(

,

)

,

{

x

|

x

R

}

Range:

[

0

,

)

,

{

y

|

y

0

}

Answered by katsaplias
1

Answer:

Its a

Step-by-step explanation:

the  denominator must always be ≠0

so you sould solve the equalation x²+1=0

⇒x²=-1 so there is not a x∈R so that this equalation =0

so Df=R

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