Math, asked by jassio, 10 months ago

the domain of the real function f(x) =1/(4-x2) is

Answers

Answered by percyjackson1
0

f(x) =1/(4-x^2)

we know that 4-x^2 cannot be equal to 0

therefore, x \neq ±2

Hence, domain of the given function f(x) is

R - {±2}

Hope it helps! Do mark it the Brainliest.

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