Question

The double of a number is greater by 48 then its half. find the number.

Answer 1

Let the number be x
Btw,
2x -48= x/2
4x-x= 96
3x= 96
x = 32

Answer 2

Let the required number is 2k ,




According to the question,

Double of 2k = 48 + half of 2k





Now,

$2(2k) = 48 + \frac{2k}{2} \\ \\ \\ = > 4k = 48 + k \\ \\ \\ = > 4k - k = 48 \\ \\ \\ = > 3k = 48 \\ \\ \\ = > k = \frac{48}{3} \\ \\ \\ = > \bold{ k = 16}$






$\boxed{ \bold{ \underline{Hence, \: required \: \: number \: \: is \: \: \: \: 2k \: = 2(16) = 32}}}$