The driver of a car makes an emergency stop by slamming on the car's brakes and skidding to a stop. How far
would the car have skidded if it had been traveling twice as fast?
(A) 4 times as far (B) the same distance (C) 2 times as far (D)the mass of the car must be known
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(A) 4 times as far the car have skidded if it had been traveling twice as fast.
Explanation:
The stopping distance is given by the formula:
Vf = Vi² + 2ad
Where,
Vf = Final speed
Vi = Initial speed
d = Stopping distance
Now,
0 = Vi² + 2ad
The distance 'd' is given as
d = Vi²/2a
The stopping distance is directly proportional to the square of the initial distance.
Thus, if the car is travelling twice the initial speed, then the distance of skidding would be four times than the obtained skidding distance.
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