The driver of a three wheeler moving with a velocity 40km h-¹ sees a child standing in the middle of the road and brings his vehicle to rest in 5 seconds just in the time to save the child . What is the average retarding force on the vehicles ? The mass of the three wheeler is 500 kg and the mass of the driver is 70 kg .
Answers
Answer:
Initial speed of the three-wheeler, u=36km/h=10m/s
Final speed of the three-wheeler, v=0 m/s
Time, t=4s
Mass of the three-wheeler, m=400 kg
Mass of the driver, m′=65kg
Total mass of the system, M=400+65=465 kg
Using the first law of motion, the acceleration (a) of the three-wheeler can be calculated as:
v=u+at
a=t(v−u)=4(0−10)=−2.5m/s2
The negative sign indicates that the velocity of the three-wheeler is decreasing with time.
Using Newton's second law of motion, the net force acting on the three-wheeler can be calculated as:
F=Ma=465×(−2.5)=−1162.5N
The negative sign indicates that the force is acting against the direction of motion of the three-wheeler.
Explanation:
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Answer:
1266.67N
Explanation:
initial velocity(u)=40km/h
=11.11m/s
final velocity(v)=o
time(t)=5s
mass of three wheeler=500kg
mass of driver=70kg
total mass=500kg +70kg
=570kg
now,
retardation(-a)=(v-u)/t
(-a)=(0-11.11)/5
(-a)=(-2.22)
a=2.22m/s^2
again,
F=ma
=570*2.22
=1266.67N