the driver of a train travelling at 40 m/s applies the brakes as a train enters a station . the train slow down at a rate of 2m/s . the platform is 400m long . will the train stop in time ?
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Answer:
Initial speed =u=40ms
−1
Acceleration =a=−2ms
−2
(Retardation, hence negative)
Final speed =v=0
Now, s= Distance train travels before stopping
Now, we know from the equations of motion that
v
2
=u
2
+2as
0=40
2
+2×(−2)×s
4s=1600⇒s=400m
So, the train covers 400m before stopping
Also, the length of platform =400m
So, the train stops in time
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