The driver of train A travelling at a speed of 54 km/h applies brakes and retards the train uniformly. The train stops
in 5 s. Another train B is travelling on the parallel with a speed of 36 km/h. Its driver applies the brakes and the train
retards uniformly and stops in 10 s. Plot speed-time graphs for both the trains on the same axis. Which of the trains
travelled farther after the brakes were applied?
Answers
Given : The driver of train A travelling at a speed of 54 km/h applies brakes and retards the train uniformly. The train stops in 5 seconds.
Another train B is travelling on the parallel with a speed of 36 km/h , Its driver applies the brakes and the train retards uniformly; train B stops in 10 seconds.
To Find : Plot speed-time graphs for both the trains on the same axis.
Which of the trains travelled farther after the brakes were applied?
Solution:
Train A = 54 km/h = 54 * 5 / 18 = 15 m/s
Time = 5 sec
Distance covered = 5 *( 15 + 0)/2 = 37.5 m
acceleration = ( 0 - 15)/5 = - 3 m/s²
Time Speed
0 15
1 12
2 9
3 6
4 3
5 0
Train B = 36 km/h = 36 * 5 / 18 = 10 m/s
Time = 10 sec
Distance covered = 10 *( 10 + 0)/2 = 50 m
a = ( 0 - 10)/10 = - 1 m/s²
Time Speed
0 10
1 9
2 8
3 7
4 6
5 5
6 4
7 3
8 2
9 1
10 0
trains B travelled farther after the brakes were applied
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Answer:
For train A:
5 u=54 km/h=54x. = 15 m/s 18
v=0;t=5s
For train B:
5 u=36 km/h = 36x = 10 m/s 18
v=0;t=10s
Distance travelled by A = Area under EF = 2/1×15×5=37.5m
Distance travelled by B = Area under CD = 2
1 x10x10-50 m
Explanation:
I think you understand