The earth (mass = 6 x 1024 kg) revolves around
the sun with an angular velocity of 2 x 10-7 rad/s
in a circular orbit of radius 1.5 x 108 km. The force
exerted by the sun on the earth, in newtons, is
(1) 36 x 1021
(2) 27 * 1039
(3) Zero
(4) 18 x 1025
Answers
PROBLEM 06 – 0675: The earth (mass = 6 × 1024 kg) revolves around the sun with
angular velocity 2 × 10–7rad/sec in a circular orbit of radius
1.5 × 108 km. The force exerted by the sun on the earth is
= ………… N
(A) 18 × 1025 (b) zero
(C) 27 × 1039 (D) 36 × 1021
Solution: Answer: (D) 36 × 1021
Force exerted by sun of earth = mw2R
given = m = 6 × 1024 kg.
w = 2 × 10–7 rad/s
R = 1.5 × 108 km
∴ F = (6 × 1024)(2 × 10–7)2(1.5 × 108 × 103)
= 36 × 1021 N
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Answer:
(a)
Explanation: