The easiest hardest question ever!?
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Answer: 60°
Step-by-step explanation:
Let the point intersected at DB and AE be O
In △ABO,
∠ OAB + ∠ ABO + ∠ AOB = 180°
60° + 50° + ∠ AOB = 180°
110° + ∠ AOB = 180°
∠ AOB = 180° - 110°
∠ AOB = 70°
In straight line AE,
∠ AOB + ∠ EOB = 180°
70° + ∠ EOB = 180°
∠ EOB = 180° - 70°
∠ EOB = 110°
In straight line DB,
∠ EOB + ∠ EOD = 180°
110° + ∠ EOB = 180°
∠ EOB = 180° - 110°
∠ EOB = 70°
In straight line DB,
∠ AOB + ∠ AOD = 180°
70° + ∠ AOD = 180°
∠ AOD = 180° - 70°
∠ AOD = 110°
Now you can say that AB ∥ DE as it shows property of Vertically Opposite angles.
then, ∠ DEA = ∠ EAB = 60°
x = 60°
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