The eccentricity of earth orbit is 0.0167. The ratio of its maximum and minimum speeds in this orbit will be
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The ratio of its maximum and minimum speeds in this orbit will be 1.033
Explanation:
According to the law of conservation of angular momentum.
mv1r1 = mv1r2
The ratio between speed.
V(max) / V(min) = 1+e / 1−e
= 1 + 0.0167 / 1 − 0.0167
= 1.0167 / 0.9833
= 1.033
Thus The ratio of its maximum and minimum speeds in this orbit will be 1.033
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