Question

The eccentricity of the ellipse 9x​2+ 5y2- 18x - 20y - 16 = 0 is??

Answer 1

Given equation can be written as, $\frac{(x-1)^{2}}{(\sqrt{5})^{2}}+\frac{(y-2)^{2}}{(3)^{2}}=1$.
Here, a=√5 and b=3 then $e=\sqrt{\frac{b^{2}-a^{2}}{b^{2}}$ since b>a.
Hence, eccentricity, e=⅔.