Physics, asked by Arkopalmajumder, 11 months ago

The echo of a sound is heard after 5 seconds.If the speed of the sound in air be 342m/s,calculate the distance of the reflectin surface

Answers

Answered by sreepragnyaachanta
3

Answer:Hope this helps you

855m is the answer

Explanation:given time = 5 seconds

Speed of sound in air = 342m/s

Since the sound heard is after reflection the distance travelled will be twice the distance between the source and the reflecting surface.

We know that v= distance/ time

342=2d/5

So 342*5=2d

1710=2d

1710/2=d

d=855m

Therefore the distance between the source of sound and reflector is 855m.

Answered by sweetisha34
1

V=342 m/s

t=5 s

let the distance be d.

we know that,

d =  \frac{v \times t}{2}

 = \frac{342 \times 5}{2}

 = 855

hope it will help you .......

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