Question

the edge length of NaCl unit cell is 564pm. What is the density of NaCl in gcm3? atomic mass of Na=23.0,cl=35.5,advogadros number=6.022x1023​

Answer 1

Answer:

Let us consider the problem.

Using the formula

ρ=

a

3

N

N

A

M

We have

ρ=

(0.564×10

−7

cm)

3

4

×

(6.023×10

23

mol

−1

)

(58.5gmol

−1

)

=2.166gcm

−3