Question

the edge length of the free cell is 508 pm . if the radius of the cation is 110 pm, the radius of the anion is ?

Answer 1

• Edge length=508pm
• Radius of cation=110pm
• Radius of anion=?

We know

$\boxed{\sf Edge\:length=Radius\;of\:cation+Radius\:of\:anion}$

$\\ \sf\longmapsto Radius\:of\:anion=Edge\:length-Radius\:of\:cation$

$\\ \sf\longmapsto Radius\;of\:anion=508-110$

$\\ \sf\longmapsto Radius\:of\:anion=398pm$