the edge of a cube is increased by 100%. The surface area of the cube is increased by
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Answered by
1
since area=6×edge^2
let area be x
therefore (6×edge^2)=x
if edge is increased by 100% therefore
new edge=2× old edge
by formula,
area=6×(edge)^2=6× (2×old edge)^2
=6×(4×edge^2)=4×(6×edge^2)=4x
therefore surface area is increased to 4 times
let area be x
therefore (6×edge^2)=x
if edge is increased by 100% therefore
new edge=2× old edge
by formula,
area=6×(edge)^2=6× (2×old edge)^2
=6×(4×edge^2)=4×(6×edge^2)=4x
therefore surface area is increased to 4 times
Answered by
7
let the edge be x
then surface area of cube =6× x^2= 6x^2
new edge 2x
then surface area of cube = 6× (2x)^2= 6×4x^2=24x^2
% increased in area = (24x^2-6x^2)×100/6x^2
=18x^2×100/6x^2
=3×100
=300
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so answer is 300%
the edge of a cube is increased by 100% then surface area of the cube is increased by 300%
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then surface area of cube =6× x^2= 6x^2
new edge 2x
then surface area of cube = 6× (2x)^2= 6×4x^2=24x^2
% increased in area = (24x^2-6x^2)×100/6x^2
=18x^2×100/6x^2
=3×100
=300
.
.
.
so answer is 300%
the edge of a cube is increased by 100% then surface area of the cube is increased by 300%
HOPE HELPS
IF YES, PLEASE MARK IT AS Brainliest
Anonymous:
maan kassam leta hun
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