Question

The edges of a triangular board are 6 cm ,8 cm , and 10 cm .The cost of painting it athe rate of 70 paise per sq.cm​

Answer 1

00000000000000001680

Answer 2

Perimeter = (6+8+10)/2

=> 24/2 = 12 cm

Herons Formulae:-

= $\sqrt{12(12-6)(12-8)(12-10)} \\\sqrt{12*6*4*2} \\\sqrt{2*6*6*2*2*2} \\2*6*2 = 24cm^2$

1 sq.cm painting costs 70 paise

24 sq.cm painting costs = 70*24 = 1680p = Rupees 16 and 80 paise (Ans)

Points:-

1) Perimeter of the sides

2) Area ( Herons Formulae)

3) Unitary Method

Have a gr8 day!!!