The effective resistance between A and B
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The resistors of 6Ω,6Ω, and 6Ω are connected in parallel,...
therefore the equivalent resistance =2Ω
and hence the rest are in series;
5Ω+2Ω+3Ω=10Ω
therefore the effective resistance between A and B is 10Ω
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When the resistances are in series, the equivalent resistance is simply the sum of the resistances connected in series. Therefore, the net effective resistance in between point A and B is Reff=5+2+3=10Ω.
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