Physics, asked by kaivaly, 3 months ago

The effective resistance of the parallel combination of two resistors of 60 Ω and 40 Ω is ______. please give with explanation ✍️✍️​

Answers

Answered by aneetacherian08
0

HAPPY NEW YEAR FRND

Answered by stefangonzalez246
0

The effective resistance of the parallel combination of two resistors of 60 Ω and 40 Ω is  24Ω .

Explanation:

  • Resistor is an electrical component which will resist the overflow of current, divide the voltages, etc.
  • Parallel Combination of two resistors, R_{eq} = \frac{R_{1} R_{2}}{R_{1}+ R_{2}}
  • The value of R_{1} = 60  , R_{2} = 40.
  • Substituting in the value of R_{eq} we get,

                                         R_{eq} = \frac{1}{{60}+ 40}} (60×40)

                                         R_{eq} = \frac{2400}{100}

                                          R_{eq} = 24

  • Hence the parallel combination of two resistors = 24 Ω.

                                         

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