Question

The efficiency of an ideal heat engine working between the freezing point and boiling point of water is

Answer 1

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Efficiency of Ideal Heat Engine, 

Using the Formula,

       η= ( 1-$\frac{T₂}{T₁}$ )
       
  Where, T₂ = Sink Temperature
                T₂ = 0° C 
               T₂   =  273 K
               

             T₁ = Source Temperature
                 = 100°C
            T₁ = 373 K

  
∴

%η = ( 1 -$\frac{T₂}{T₁}$  ) x 100 

 = ( 1- $\frac{273}{373}$  ) x 100

=   $\frac{100}{373}$ x 100

= 26.8 % 


↔ Thus the Efficiency of Ideal Heat Engine is 26.8 % . ↔

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Hope it Helps .

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Answer 2

According to Carnot theory ,
The efficiency of an ideal heat engine is given by
η = 1 - T₂/T₁
Where T₁ is the temperature of source ,
T₂ is the temperature of sink ,
η is the efficiency of heat engine .
Here you should understand that sink's temperature < source temperature

We know, freezing point of water = 0°C = 273K
Boiling point of water = 100°C = 373K
∴ T₁ = 373K , T₂ = 273K
∴η = 1 - 273/373 = 1 - 0.732 = 0.268

Hence, % efficiency = 100η = 26.8 %