Question

The effort arm of a lever is 5 m long and its load arm is 2 m long. Find the effort needed to raise a load of 70 kg wt.​

Answer 1

Answer:

28 N

Explanation:

Rotational equilibrium is maintained in a lever. Net upward rotational torque is equal to downward torque.

So Load force x length of load arm= Effort force x Length of effort arm

       Effort = 70 x 2 /5

                 = 28 N

Answer 2

Explanation:

Sorry for a long explanation in the picture.

Just for your understanding.

Anyways here is your answer.