Question

The effort arm of an ideal lever of class I is 2 m long and the load arm is 50 cm long. How much load can be lifted by using an effort of 60 N?



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Answer 1

Explanation:

Since the fulcrum lies in between the load and effort, it is class I lever.

Mechanical advantage (M.A.) of levers is given by,

M.A.=

effort arm

load arm

=

50cm

10cm

Thus, mechanical advantage , M.A. = 5.

Given, effort (E)=10N, Load(L)=?

∴L=E×M.A.

=10×5=50N

Answer 2

Answer:

ok

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