Question

The electric current in a charging R-C circuit is given by i = i e^(-t/RC) where i , R and C are constant parameters of the circuit and t is time . Find the rate of change of current at

(a)t=0
(b)t=RC
(c)t=10 RC

Answer 1

Thanks for asking the question!

ANSWER::

Given :-i = i₀e^(-t/RC)

Rate of change of current = di/dt = d i e^(-t/RC)/dt = i₀d e^(-t/RC)/dt                                                                                      = (-i x e^(-t/RC)) / RC
(a) t = 0 , di /dt = -i/RC

(b) t = RC , di / dt = -i /RCe

(c) t = 10 RC , di / dt = -i₀/RCe¹⁰

Hope it helps!