The electric current in a circuit varies from + 2 A
to - 2 A in a time interval of 10-? A s. Another coil
of resistance 2092 and inductance 2 H is placed
near it. What will be the induced current in the
second coil ?
3.
Answers
Answered by
0
Answer:
using Faraday's law
The magnitude of emf induced ε=l
△t
△I
so the current in the coil =
R
ε
=
R
L
△t
△I
△I=2−(−2)=4A,△t=10
−2
s,L=2H and R=20Ω
I
induced
=
20
2 × 10 −2
4
=40A
Explanation:
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