The electric current in electric bulb is 22 mA. What is the charge flowing through the filament in 4s ?
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Answer:
88 mC
Explanation:
Current-charge relationship is
Q = it
= 22 mA × 4 s
= 22 × 10^-3 A × 4 s
= 88 × 10^-3 As
= 88 × 10^-3 C
= 88 mC
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