Question

The electric field at (30, 30) cm due to a charge of -8nC at the origin in NC^-1 is​

Answer 1

Answer:

E= - $4$×$10^{7}$ N/C

Explanation:

The electric field due to a charge at d distance away is

E = $\frac{1}{4π∈}$ $\frac{q}{d^{2} }$

The charge is at (30,30) cm from the origin. So, the distance of that point from the origin is $\sqrt{30^{2}+30^{2} } =30\sqrt{2} cm$

E= (9×$10^{9}$) (-8)/(30$\sqrt{2}$)$^{2}$

E= - $4$×$10^{7}$ N/C