Question

The electric field at a point due to a point charge is 30 N/C, and the electric potential at that point is 15 J/C. calculate the distance of the point from the charge and the magnitude of the charge.

Answer 1

Explanation:

The electric field at a point due to a point charge is 30 N/C, and the electric potential at The electric field at a point due to a point charge is 30 N/C, and the electric potential at that poiThe electric field at a point due to a point charge is 30 N/C, and the electric potential at that point is 15 J/C.nt is 15 J/The electric field at a point due to a point charge is 30 N/C, and the electric potential at that point is 15 J/C.C.that point is 15 J/C.

Answer 2

Answer

For point charge

E=V/r

Given

V=15J/C

E=30N/C

Distance from point charge, r=?

Point charge, q=?

r=V/E=15/30=0.5m

V=

4πε

0

r

q

q=4πε

0

rV

q=

9×10

9

1

×0.5×15

q=0.83×10

−9

C

q=0.83nC