the electric field at a point in the figure if net force on q is zero then value of q/q is
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your question is incomplete ,
Well, I attached figure as mentioned in figure .
net force on Q is zero , it means Q and q are in opposite nature .
Let Q is positive nature and q is negative nature
Then, force between Q and Q will be repulsion,
And force between Q and q will be attraction,
Now, net force act on Q =net force act by q - net force act by Q on Q = 0
net force act by q on Q = net force act by Q on Q
![\sqrt{[\frac{KqQ}{r^2}]^2+[\frac{KqQ}{r^2}]^2}=\frac{KQ.Q}{(\sqrt{2}r)^2}\\\\\sqrt{2}\frac{KqQ}{r^2}=\frac{KQ^2}{2r^2}\\\\2\sqrt{2}qQ=Q^2\\\\2\sqrt{2}=\frac{Q.\cancel{Q}}{q.\cancel{Q}}\\\\\frac{Q}{q}=2\sqrt{2}](https://tex.z-dn.net/?f=%5Csqrt%7B%5B%5Cfrac%7BKqQ%7D%7Br%5E2%7D%5D%5E2%2B%5B%5Cfrac%7BKqQ%7D%7Br%5E2%7D%5D%5E2%7D%3D%5Cfrac%7BKQ.Q%7D%7B%28%5Csqrt%7B2%7Dr%29%5E2%7D%5C%5C%5C%5C%5Csqrt%7B2%7D%5Cfrac%7BKqQ%7D%7Br%5E2%7D%3D%5Cfrac%7BKQ%5E2%7D%7B2r%5E2%7D%5C%5C%5C%5C2%5Csqrt%7B2%7DqQ%3DQ%5E2%5C%5C%5C%5C2%5Csqrt%7B2%7D%3D%5Cfrac%7BQ.%5Ccancel%7BQ%7D%7D%7Bq.%5Ccancel%7BQ%7D%7D%5C%5C%5C%5C%5Cfrac%7BQ%7D%7Bq%7D%3D2%5Csqrt%7B2%7D "\sqrt{[\frac{KqQ}{r^2}]^2+[\frac{KqQ}{r^2}]^2}=\frac{KQ.Q}{(\sqrt{2}r)^2}\\\\\sqrt{2}\frac{KqQ}{r^2}=\frac{KQ^2}{2r^2}\\\\2\sqrt{2}qQ=Q^2\\\\2\sqrt{2}=\frac{Q.\cancel{Q}}{q.\cancel{Q}}\\\\\frac{Q}{q}=2\sqrt{2}")
hence, Q/q = 2√2
Well, I attached figure as mentioned in figure .
net force on Q is zero , it means Q and q are in opposite nature .
Let Q is positive nature and q is negative nature
Then, force between Q and Q will be repulsion,
And force between Q and q will be attraction,
Now, net force act on Q =net force act by q - net force act by Q on Q = 0
net force act by q on Q = net force act by Q on Q
hence, Q/q = 2√2
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