Question

the electric field intensity at a point at a distance 2 m from a charge q is E the amount of work done in bringing a charge of 2 coulomb from infinity to this point will be​

Answer 1

Answer:

Explanation:

If any doubt ask me

Answer 2

Answer:

Amount of work done is 4v Jule.

Explanation:

Electric potential at a point at distance 2m from charge q is v.

To find- Amount of work done charge of 2 Coulomb from point.

We have distance between q and A is 2m.

At infinity velocity is 0.

Electric field at A,

E$= \frac{kq}{ {2}^{2} } = \frac{kq}{4}$

We know,

$w = q( \frac{kq}{2} - 0)$

$w = 2 \times \frac{kq}{2}$

$w = 4v$

Where

$v = \frac{kq}{2}$

Amount of work done is 4v Jule.