the electric field intensity at a point in vacuum is equal to
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electric field intensity is the strength of electric field act by a charge particle on any point. Or you can say that electric field intensity is the force per unit charge.
according to Coulombs law,
F = KQ₁Q₂/r², where Q₁ , Q₂ are charged particle and separation between them is r.
For Electric field intensity , Assume Q₂ is unit charged particle e.g., Q₂ = 1 unit
Q₁ = Q , so, electric field intensity at r distance due to Q charge ,E = F/Q₂
E = KQ₁Q₂/r² = KQ/r²
Hence, simply you can say that electric field intensity at distance r due to charge particle Q is E = KQ/r² in vacuum k = 1/4πε₀
so, E = Q/4πε₀r²
according to Coulombs law,
F = KQ₁Q₂/r², where Q₁ , Q₂ are charged particle and separation between them is r.
For Electric field intensity , Assume Q₂ is unit charged particle e.g., Q₂ = 1 unit
Q₁ = Q , so, electric field intensity at r distance due to Q charge ,E = F/Q₂
E = KQ₁Q₂/r² = KQ/r²
Hence, simply you can say that electric field intensity at distance r due to charge particle Q is E = KQ/r² in vacuum k = 1/4πε₀
so, E = Q/4πε₀r²
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