the electric field intensity inside a hollow spherical charged conductor is
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a sperical gaussian surface which lies just inside the conducting shell. Now, the gaussian surface encloses no charge, since all of thecharge lies on the shell, so it follows from Gauss' law, and symmetry, that the electric field of the shell is zero.
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a sperical gaussian surface which lies just inside the conducting shell. Now, the gaussian surface encloses no charge, since all of thecharge lies on the shell, so it follows from Gauss' law, and symmetry, that the electric field of the shell is zero.
HOPE THIS WAS HELPFUL
PLZZZ MARK AS BRAINLIEST ANSWER
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