Physics, asked by partvisingh7743, 1 year ago

The electric field intensity produced by the radiations coming from a 100 W bulb at a 3 m distance is E. The electric field intensity produced by the radiations coming from 50 W bulb at the same distance is

Answers

Answered by saeedpathan888
0

answer

Power of bulb=100W

Intensity of Electric field at a distance 3m is E.

The electric field intensity is given by:

E=

A

P

⇒E=

πr

2

100

=

π×3

2

100

=

100

watt/m

2

Similarly, E at a distance of 3m produced by 50W bulb is:

⇒E

1

=

πr

2

50

watt/m

2

=

50

watt/m

2

E

1

E

=

100

÷

50

E

1

E

=

100

×

50

=2

⇒E

1

=

2

E

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