Physics, asked by AMIT4134, 9 months ago

The electric field of a plane electromagnetic wave in vacuum is represented by vecE_x=0, vecE_y=0.5 cos[2pixx10^8(t-x/c)], vecE_z=0 (a) What is the direction of propagation of electromagnetic wave? (b) Determine the wavelength of the wave. (c) Compute the component of associated magnetic field.

Answers

Answered by Anonymous
1

Answer:

Equation second shows that the electromagnetic wave travels along the positive x-axis.

(b) Wavelength of wave, `lambda=c/v=c/((omega//2pi))=(2pic)/omega=(2pixx(3xx10^8))/(2pixx10^8)=3.0m`

(c) Since the magnetic ffield is perpendicular to electric feild as well as the direction of propagation of

e.m. wave hence magnetic field must be varying along z-axis. Therefore

`vecB_x=0, vecB_y=0, and vecB_z=0.5/(3xx10^8)cos [2pixx10^8(t-x//c)] [:' E//B=c

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