Question

the electric field strength at a distance of 1.10x10 ^ 1 cm from a charge of 5.000x10^-6 uc?​

Answer 1

Answer:

$\\\tt 37.19 \times 10^7 \dfrac{N}{C}$

Explanation:

$\\\tt E = \dfrac{1}{4 \pi \epsilon _{\circ}} \dfrac{5 \times 10^{-6}C}{(1.1 \times 10^{-2})^2} \\= 9 \times 10^{9} \times \dfrac{5 \times 10^{-6}C}{(1.1 \times 10^{-2})^2} \\=37.19 \times 10^7 \dfrac{N}{C}$