Question

The electric field strength at a point on axial line is 10N/C for an electric dipole. What will be the electric field at a point on equatorial line for the same distance ?​

Answer 1

Answer:

E = 20 N/C

Explanation:

Answer 2

QUESTION :-

What is the ratio of strength of electric field at a point on axial line and a point on same distance a equitorial line of an electric dipole of very small length​?

SOLUTION :-

The ratio of the strength of an electric field at a point on axial line and a point on same distance at an equitorial line of an electric dipole of very small length is 2:1

- A force which would be exerted on other charged particles in a region around a charged particle object is called electric field

- The formula is given by equation,

E = 1 × 2P /4 πε0 r^3

- With the help of axial line of dipole the other two charges , i.e , positive and negative charges pass through it.

- The electric field at the axial line is equal to,

E(axial) = 1 × 2P /4 πε0 r^3

- The electric field at equatorial line is equal to,

E(equatorial)= 1 × P /4 πε0 r^3

- The ratio of the electric field intensity at the point on the equatorial line to the electric field at the point on axial line is,

- E(axial)/E(equatorial) =

1 × 2P /4 πε0 r^3/ 1 × P /4 πε0r^3

= 2/1

- *E(axial) : E(equatorial) = 2:1*

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