The electric potential and electric field at any given position due to a point charge are 600V and 200 N/C respectively. Then magnitude of point charge would be
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The magnitude of the point charge is 0.2uC.
Given:
Electric potential = 600V
Electric charge = 200N/C
To Find:
The magnitude of the point charge
Solution:
v = 600V = k8/x
E = 200 = k8/x²
Therefore,
x = 600/200
x = 3
Now,
Q = 600 × 3/ 9 × 10~9
Q = 1800 / 9 × 10~9
Q = 2 × 10~7
Q = 0.2
Answer: The magnitude of the point charge is 0.2uC.
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