Question

the electric potential at a point in an electric Field is 20V. how much work will have to be done to move an electrone from that point to a point just outside the field​

Answer 1

Answer:

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Answer 2

Answer:

32×10^-19J

Explanation:

electric potential at infinity= 0V

electric potential at given point=20V

potential difference= 20-0=20V

potential difference = work done/charge

20×(1.6×10^-19) = work done

32×10^-19J