Question

The electric potential energy of a system of two positive point charges of 1 C each placed in air 1m apart is :

(a) 9*10^3 J
(b) 9*10^-3 J
(c) 9*10^9 J​

Answer 1

The electric potential energy of system of charges is 9 × 10⁹ J. hence, the correct option is (d).

We have to find the electric potential energy of a system of two positive point charges of 1C placed in air 1 m apart.

Electric potential energy :

• Electric potential energy is a type of potential energy that results from conservative Coulomb force.
• It is the amount of energy needed to move an charge against the electric field.
• Standard formula to find the electric potential energy of two charges q and Q which is separated r from each other, is U = kqQ/r.

Here, q = Q = 1 C, r = 1 m

⇒ U = (9 × 10⁹ × 1 × 1 )/(1)

= 9 × 10⁹ J

Therefore the electric potential energy of system is 9 × 10⁹ J.

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