Question

The electrical resistence of 0.08m caustic soda solution is 5000 when placed in coloumn of diameter 2cm and length 50 cm the conductivity of solution

Answer 1

Answer:

A = πr2 = 3.14 x (0.5)2 cm2 = 0.785 cm2 l = 50 cm.

constant, the resistance of the solution in the cell and conductivity of the solution.

Answer 2

The conductivity of the solution is 4150 scm²mol-1.

Given:

The electrical resistance of 0.08m caustic soda solution is 5000 when placed in a column with a diameter of 2cm and length of 50 cm.

To Find:

The conductivity of the solution

Solution:

To find the conductivity of the solution we will follow the following steps:

$r = p \frac{l}{a}$

l is length = 0.5 metre

a is area = πr1² = 3.14 × (0.01)²

r1 is radius = 0.01m

r is the resistance while p is resistivity.

$5000 = p \frac{0.5}{3.14 \times 1 \ time {10}^{ - 4} }$

$Conductivity = \frac{k \times 1000}{c}$

$k \: = \frac{1}{p}$

So,

$k = \frac{1}{p} = \frac{0.5}{3.14 \times 1 \times {10}^{ - 4} \times 5000 } = \frac{0.5}{0.3×5} = 0.332s {cm}^{ - 1}$

Now, putting the value of k in the above equation we get,

$Conductivity = \frac{332 \times 1000}{0.08} = 4150 \: s {cm}^{2} {mol}^{ - 1}$

Henceforth, the conductivity of the solution is 4150 scm²mol-1.

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