Physics, asked by jassmeet771, 10 months ago

The electrical resistivities of four materials P, Q, R and S are given below P
6.84 × 10−8 Ωm
Q
1.70 × 10−8 Ωm
R
1.0 × 1015 Ωm
S
11.0 × 10−7 Ωm
Which material will you use for making (a) heating element of electric iron (b) connecting wires of electric iron (c) covering of connecting wires? Give reason for your choice in each case.; The electrical resistivities of four materials P, Q, R and S are given below

Answers

Answered by bhuvna789456
8

(a) heating element of electric iron - Material S  11.0 × 10−7 Ωm

(b) connecting wires of electric iron - Fabric Q   1.70 × 10−8 Ωm

(c) covering of connecting wires -  Fiber R 1.0 × 1015 Ωm

Explanation:

(a) Material S is used to create an electrical iron heating element because it has a large resistivity.( Electrical resistivity is the calculation of how well the bringing electrical current resists an object. )

(b) Fabric Q is used to make an electric iron's linking wires, as it has minimum resistivity.

(c) Fiber R will be used to protect the connecting wires, because it is highly resistive.

You can get all the answers of Chapter 1 in the link below:    

https://brainly.in/question/14961133

   

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Answered by LyricalVoltaik
5

Explanation:

(a) S; because it has high resistivity of 11 X 10-7ohm-m (it is actually nichrome).

S; because it has high resistivity of 11 X 10-7ohm-m (it is actually nichrome).(b) Q; because it has very low resistivity of 1.7 X 10-8ohm-m (it is actually copper).

S; because it has high resistivity of 11 X 10-7ohm-m (it is actually nichrome).(b) Q; because it has very low resistivity of 1.7 X 10-8ohm-m (it is actually copper).(c) R; because it has very very high resistivity of 1.0 X 1015ohm-m (it is actually rubber).

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