Question

[ the electron in the hydrogen atom circles around the proton with a speed of 2.18×10^(6)m/s in an orbit of radius 5.3×10^(-11)m . (a) what is the equivalent dipole moment? (b) what magnetic field does it produce at the proton? ]

Answer 1

Answer:

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Explanation:

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By de-Broglie's theory, the wavelength of any particle λ=

p

h

and p=m

V

∴λ=

m

V

h

V

=

5

c

=

5

3×10

8

∴λ=

9×10

−31

×3×10

8

6.63×10

−34

×5

=1.23×10

−11

m

Answer:- 1.23×10

−11

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