Question

The electronic configuration of an element X is 2,8,2 and find the no of electron present in the atom of element X

Answer 1

Answer:

electronic configuration of X =

${1s}^{2} {2s}^{2} {3s}^{2} {3p}^{6}$

atomic number of X = 12

this is metal atom

magnesium (Mg) have 12 atomic number .

no of electrons = no of proton = atomic number of element

atomic number is 12

the number of electrons present in this X element (Mg) is 12

oxidation state of Mg is +2 ..

This is your answer................

thanks..

Answer 2

It helpful for you☺ make me brainlest☺☺☺