The electronic configuration of element X is 2, 8, 8, 1 and the electronic configuration of element Y is 2, 8, 7. Then the type of bond formed between these two elements is _________
(A) covalent bond
(B) hydrogen bond
(C) metallic bond
(D) ionic bond
Answers
If they share valence e-cig to complete octet than
A) Covalent Bond..
Will be formed
And
If X donates one e-cig and Y gains one e-cig than bond will be
D) Ionic Bond ....
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(D) Ionic bond .
EXPLANATION :
⏩ The ionic bond is also called electrovalent bond . This bond is formed generally due to the transfer of electrons .
⏩ Covalent bonds are formed due to the sharing of electrons but ionic bonds are formed due to electron transfer .
⏩ The ionic bond is a chemical bond formed between electropositve metals and electronegative non metals .
⏩ In the given case X has an electronic configuration of 2 , 8 , 8 , 1 which means that it contains 1 valence outermost electron .
⏩ Y has an electronic configuration of 2 , 8 , 7 which means that it contains 7 outermost electrons .
⏩ We know that an atom tends to attain stable electronic configuration to its nearest noble gas . Here the element X needs to donate 1 electron to complete its octet .
⏩ On the other hand , the element Y requires to accept 1 electron so as to complete its octet ,
⏩ Thus there will be transfer of electrons from X to Y .
⏩ After the transfer X will turn into a positive univalent ion with a deficit of one electron .
⏩ Y will turn into a negative univalent ion with an excess of one electron .
⏩ The bond will be ionic bond as there is transfer of electrons in this case .