Question

The electronic configuration of element X is 2, 8, 8, 1 and the electronic configuration of element Y is 2, 8, 7. Then the type of bond formed between these two elements is _________
(A) covalent bond
(B) hydrogen bond
(C) metallic bond
(D) ionic bond

Answer 1

If they share valence e-cig to complete octet than

A) Covalent Bond..

Will be formed

And

If X donates one e-cig and Y gains one e-cig than bond will be

D) Ionic Bond ....

Mark Brainliest if it is helpful to you

Answer 2

(D) Ionic bond .

EXPLANATION :

⏩ The ionic bond is also called electrovalent bond . This bond is formed generally due to the transfer of electrons .

⏩ Covalent bonds are formed due to the sharing of electrons but ionic bonds are formed due to electron transfer .

⏩ The ionic bond is a chemical bond formed between electropositve metals and electronegative non metals .

⏩ In the given case X has an electronic configuration of 2 , 8 , 8 , 1 which means that it contains 1 valence outermost electron .

⏩ Y has an electronic configuration of 2 , 8 , 7 which means that it contains 7 outermost electrons .

⏩ We know that an atom tends to attain stable electronic configuration to its nearest noble gas . Here the element X needs to donate 1 electron to complete its octet .

⏩ On the other hand , the element Y requires to accept 1 electron so as to complete its octet ,

⏩ Thus there will be transfer of electrons from X to Y .

⏩ After the transfer X will turn into a positive univalent ion with a deficit of one electron .

⏩ Y will turn into a negative univalent ion with an excess of one electron .

⏩ The bond will be ionic bond as there is transfer of electrons in this case .