Question

The electronic configuration of metal 'A' is 2,8,1 and that of metal 'B' is 2,8,2. Which of the two metals is more reactive? Write their reaction with dilute hydrochloric acid.​

Answer 1

Answer:

If the number of electrons in the outermost orbit is less, then the metal is more reactive. Metal A contains one electron in the outermost shell, while metal B contains two electrons. Hence, metal A is more reactive than metal B. Metal A is sodium and metal B is magnesium. Reactions of Na and Mg with dil. HCl are, <br>

underset("Sodium")(2Na)+2HCl rarr underset(" chloride")underset("Sodium")(2NaCl_((aq)))+underset("Hydrogen")(H_(2(g)))

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underset("Magnesium")(Mg)+underset("dil. HCl")(2HCl)rarrunderset("chloride")underset("Magnesium")(MgCl_(2))+underset("Hydrogen")(H_(2(g)))

Answer 2

Answer:

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