The electrons in the atoms of two elements P and Q are distributed in three
shells having 1 and 7 electrons in their outermost shells.
i) Write the group numbers in which these elements are placed in the modern
periodic table.
ii) Write the electronic configuration of P and Q and iii)the molecular formula
of
the compound formed between P and Q.
plz do answer it fast
Answers
Answer:
i)P is placed in Group 1.
Q is placed in Group 17.
ii)Now this is a tricky question.
Pay attention , you must be thinking that only we know the number of electrons in the third shell but what about the first two shells? Well, its easy.
Given the electrons of P and Q are divided into three shells so from here we get to know its Period 3 as no. of shells tells us the period no. and we already know that its Group 1. So element P in period 3 Group 1 is Na( sodium) . So electronic configuration of Na is 2,8,1.
Similarly, Q belongs to period 3 too as its electrons are divided into three shells and its Group is 17. So, the element is Cl. Electronic configuration of Cl is 2,8,7.
Therefore, P-2,8,1
Q-2,8,7
iii) Molecular formula is NaCl.
Step-by-step explanation:
Hope this helps..