the electrostatic force between charge of 200 microcoulombs and 500 microcoulombs placed in free space is 5 into 10 ^ - 2 neutrons find the distance between the two charges
Answers
If two charges of 200µC and 500µC are placed in free space with a force of 5*10⁻² N between them then the distance between the two charges is 1.34 * 10² m.
Explanation:
It is given,
Charge q₁ = 200 μC = 200 * 10⁻⁶ C = 2 * 10⁻⁴ C
Charge q₂ = 500 μC = 500 * 10⁻⁶ C = 5 * 10⁻⁴ C
The electrostatic force between these two charges i.e., F = 5 * 10⁻² N
Let the distance between the two charges be denoted as “d” meter.
Now, based on Newton’s Coulombs Law, we have the formula as,
F = [k q₁ q₂] / d² …… [where k = coulomb’s constant = 9 * 10⁹ Nm²/C²]
Therefore, by substituting the given values in the formula, we get
5 * 10⁻² = [9 * 10⁹ * 2 * 10⁻⁴ * 5 * 10⁻⁴] / d²
⇒ d² = [9 * 10⁹ * 2 * 10⁻⁴ * 5 * 10⁻⁴] / [5 * 10⁻²]
⇒ d² = [9*2*10^(9-4-4+2)]
⇒ d² = 18000
⇒ d = 134.16 ≈ 1.34 * 10² m
Thus, the distance between the two charges is 1.34 * 10² m.
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