The electrostatic force on a small sphere of charge 0.4 uC due to another small sphere of charge
-0.8 uC in air is 0.2 N.
(a) What is the distance between the two spheres ?
(b) What is the force on the second sphere due to the first ?
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Answer:
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Explanation:
a) f = k q1q2/d²
d = √kq1q2/f = √0.32x10∧-12/9x10∧9 = √320/3 = 8√5/3 m.
(b) What is the force on the second sphere due to the first = 0.2 N.
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B:-
(b) Both the charged spheres being oppositely
charged apply attractive electric force on each
other. The forces applied by the spheres on
each other are equal in magnitude. Therefore,
the first sphere attracts the second sphere
with a force of 0.2 N.
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