The electrostatic potential energy of two charges,1 mew coulomb each ,place 1 m apart in vaccum is
Answers
Answered by
2
Two charges are given , each of magnitude = 1μC
separation between charges = 1m
potential energy = Kq₁q₂/r
Given, q₁ = q₂ = 1μC = 10⁻⁶C
r = 1m
Now, potential energy = 9 × 10⁹ × 10⁻⁶ × 10⁻⁶/1
= 9 × 10⁹ × 10⁻¹² = 9 × 10⁻³ J
Hence, potential energy = 0.009 J
separation between charges = 1m
potential energy = Kq₁q₂/r
Given, q₁ = q₂ = 1μC = 10⁻⁶C
r = 1m
Now, potential energy = 9 × 10⁹ × 10⁻⁶ × 10⁻⁶/1
= 9 × 10⁹ × 10⁻¹² = 9 × 10⁻³ J
Hence, potential energy = 0.009 J
Similar questions