Question

the electrostaticforce between two charges is 800 N in air. when it is placed in water, what will be the force​

Answer 1

Answer:

10 N.

Explanation:

F = Kq1q2/r²,

where, for air , €=1, K=1

Therefore, q1q2/r²=800.

Now, in water,

€=80 and hence K=1/80

F in H2O= 800/80= 10N.